The equations \(\displaystyle{y}=-{x}+{4}{\quad\text{and}\quad}{y}={12}{x}-{8}{y}\)

\(= 21x−8\) form a system of linear equations.

The table below shows the y-value for each equation at six different values of x. \(xy=−x+4y=12x−804−822−740−66−2−58−4−410−6−3\)

What can you conclude from the table?

A. The system has one solution, when x=0.

B. The system has one solution, when x=4.

C. The system has one solution, when x=8.

D. The system has no solution.